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Algebra / Linear inequalities in one or two variables Difficulty: Medium

y>4x+8

For which of the following tables are all the values of x and their corresponding values of y solutions to the given inequality?

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Explanation

Choice A is correct. In each choice, the values of x are 2 , 4 , and 6 . Substituting the first value of x , 2 , for x in the given inequality yields y>42+8, or y>16. Therefore, when x = 2 , the corresponding value of y must be greater than 16 . Of the given choices, only choice A is a table where the value of y corresponding to x = 2 is greater than 16 . To confirm that the other values of x in this table and their corresponding values of y are also solutions to the given inequality, the values of x and y in the table can be substituted for x and y in the given inequality. Substituting 4 for x and 30 for y in the given inequality yields 30>44+8, or 30>24, which is true. Substituting 6 for x and 41 for y in the given inequality yields 41>46+8, or 41>32, which is true. It follows that for choice A, all the values of x and their corresponding values of y are solutions to the given inequality.

Choice B is incorrect. Substituting 2 for x and 8 for y in the given inequality yields 8>42+8, or 8>16, which is false.

Choice C is incorrect. Substituting 2 for x and 13 for y in the given inequality yields 13>42+8, or 13>16, which is false.

Choice D is incorrect. Substituting 2 for x and 13 for y in the given inequality yields 13>42+8, or 13>16, which is false.